Gravitation NCERT Solutions Class 11 Physics - Solved Exercise Question 8.24

Question 8.24:
A spaceship is stationed on Mars. How much energy must be expended on the spaceship to launch it out of the solar system? Mass of the space ship = 1000 kg; mass of the Sun = 2 × 1030 kg; mass of mars = 6.4 × 1023 kg; radius of mars = 3395 km; radius of the orbit of mars = 2.28 × 108kg; G= 6.67 × 10–11 m2kg–2.
Solution:
Mass of the spaceship, ms = 1000 kg
Mass of the Sun, M = 2 × 1030 kg
Mass of Mars, mm = 6.4 × 10 23 kg
Orbital radius of Mars, R = 2.28 × 108 kg =2.28 × 1011m
Radius of Mars, r = 3395 km = 3.395 × 106 m
Universal gravitational constant, G = 6.67 × 10–11 m2kg–2
Potential energy of the spaceship due to the gravitational attraction of the Sun = -GMms / R
Potential energy of the spaceship due to the gravitational attraction of Mars = -GMmms / r
Since the spaceship is stationed on Mars, its velocity and hence, its kinetic energy will be zero.
Total energy of the spaceship =  -GMms / R -  GMmms / r
= -Gms[ (M / R) + (mm / r) ]
The negative sign indicates that the system is in bound state.
Energy required for launching the spaceship out of the solar system
= – (Total energy of the spaceship)
= Gms[ (M / R) + (mm / r) ]
= 6.67 X 10-11 X 103 X [ (2 X 1030 / 2.28 X 1011) + (6.4 X 1023 / 3.395 X 106 ) ]
= 596.97 X 109  =  6 X 1011 J

No comments:

Post a Comment