__Question 5.8__:

__Solution__:Initial speed of the three-wheeler,

*u*= 36 km/h = 10 m/s

*v*= 0 m/s

Time,

*t*= 4 s

Mass of the three-wheeler,

*m*= 400 kg

Mass of the driver,

*m*' = 65 kg

Total mass of the system,

*M*= 400 + 65 = 465 kg

Using the first law of motion, the acceleration (

*a*) of the three-wheeler can be calculated as:

*v = u + at*

∴ a = (v - u) / t = (0 - 10) / 4 = -2.5 ms

^{-2}

The negative sign indicates that the velocity of the three-wheeler is decreasing with time.

Using Newton’s second law of motion, the net force acting on the three-wheeler can be calculated as:

*F*=

*Ma*

= 465 × (–2.5) = –1162.5 N

The negative sign indicates that the force is acting against the direction of motion of the three-wheeler.

## No comments:

## Post a Comment