Question 5.30:
Angle of banking, θ = 15°
For radius r, of the loop, we have the relation:
tan θ = v2 / rg
r = v2 / g tan θ
= 2002 / (10 X tan 15)
= 4000 / 0.26
= 14925.37 m
= 14.92 km
An
aircraft executes a horizontal loop at a speed of 720 km/h with its
wings banked at 15°. What is the radius of the loop?
Solution:
Speed of the aircraft, v = 720 km/h = 720 X 5 / 18 = 200 m/s
Acceleration due to gravity, g = 10 m/s2Speed of the aircraft, v = 720 km/h = 720 X 5 / 18 = 200 m/s
Angle of banking, θ = 15°
For radius r, of the loop, we have the relation:
tan θ = v2 / rg
r = v2 / g tan θ
= 2002 / (10 X tan 15)
= 4000 / 0.26
= 14925.37 m
= 14.92 km
No comments:
Post a Comment