Question 5.4:
One end of a string of length l is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v the net force on the particle (directed towards the centre) is:
(i) T, (ii) T - mv2 / l, (iii) T + mv2 / l, (iv) 0
T is the tension in the string. [Choose the correct alternative].
F = T = mv2 / l
Where F is the net force acting on the particle.
One end of a string of length l is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v the net force on the particle (directed towards the centre) is:
(i) T, (ii) T - mv2 / l, (iii) T + mv2 / l, (iv) 0
T is the tension in the string. [Choose the correct alternative].
Solution:
Answer: (i)
When a particle connected to a string revolves in a
circular path around a centre, the centripetal force is provided by the
tension produced in the string. Hence, in the given case, the net force
on the particle is the tension T, i.e., Answer: (i)
F = T = mv2 / l
Where F is the net force acting on the particle.
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